Base | Representation |
---|---|
bin | 11110010010100111111011… |
… | …100111101111101100100011 |
3 | 122110200211021000201122202012 |
4 | 132102213323213233230203 |
5 | 114430144030330321402 |
6 | 1151200552355143135 |
7 | 40026626035024313 |
oct | 3622477347575443 |
9 | 573624230648665 |
10 | 133221222120227 |
11 | 394a28918a913a |
12 | 12b371b98a4aab |
13 | 5944927049837 |
14 | 24c7d278a9443 |
15 | 10605ca437452 |
hex | 7929fb9efb23 |
133221222120227 has 2 divisors, whose sum is σ = 133221222120228. Its totient is φ = 133221222120226.
The previous prime is 133221222120187. The next prime is 133221222120251. The reversal of 133221222120227 is 722021222122331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133221222120227 - 214 = 133221222103843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133221222120193 and 133221222120202.
It is not a weakly prime, because it can be changed into another prime (133221222120257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610611060113 + 66610611060114.
It is an arithmetic number, because the mean of its divisors is an integer number (66610611060114).
Almost surely, 2133221222120227 is an apocalyptic number.
133221222120227 is a deficient number, since it is larger than the sum of its proper divisors (1).
133221222120227 is an equidigital number, since it uses as much as digits as its factorization.
133221222120227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 133221222120227 its reverse (722021222122331), we get a palindrome (855242444242558).
The spelling of 133221222120227 in words is "one hundred thirty-three trillion, two hundred twenty-one billion, two hundred twenty-two million, one hundred twenty thousand, two hundred twenty-seven".
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