Base | Representation |
---|---|
bin | 1100000111011101000110… |
… | …1110000111101110011111 |
3 | 1202011120221212102211020222 |
4 | 3001313101232013232133 |
5 | 3221232342300111221 |
6 | 44200050104231555 |
7 | 2543332556360633 |
oct | 301672156075637 |
9 | 52146855384228 |
10 | 13322212113311 |
11 | 4276a11479532 |
12 | 15b1b25a6b5bb |
13 | 758382574a2a |
14 | 340b27160dc3 |
15 | 18181bdc29ab |
hex | c1dd1b87b9f |
13322212113311 has 2 divisors, whose sum is σ = 13322212113312. Its totient is φ = 13322212113310.
The previous prime is 13322212113293. The next prime is 13322212113383. The reversal of 13322212113311 is 11331121222331.
It is a weak prime.
It is an emirp because it is prime and its reverse (11331121222331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13322212113311 - 218 = 13322211851167 is a prime.
It is a super-3 number, since 3×133222121133113 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13322212113391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661106056655 + 6661106056656.
It is an arithmetic number, because the mean of its divisors is an integer number (6661106056656).
Almost surely, 213322212113311 is an apocalyptic number.
13322212113311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13322212113311 is an equidigital number, since it uses as much as digits as its factorization.
13322212113311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296, while the sum is 26.
Adding to 13322212113311 its reverse (11331121222331), we get a palindrome (24653333335642).
The spelling of 13322212113311 in words is "thirteen trillion, three hundred twenty-two billion, two hundred twelve million, one hundred thirteen thousand, three hundred eleven".
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