Base | Representation |
---|---|
bin | 11110010010101000110110… |
… | …100000010000001111101101 |
3 | 122110200220210212121202200121 |
4 | 132102220312200100033231 |
5 | 114430203041230342031 |
6 | 1151201234405124541 |
7 | 40026662361665545 |
oct | 3622506640201755 |
9 | 573626725552617 |
10 | 133222210012141 |
11 | 394a3249501a38 |
12 | 12b374346b9751 |
13 | 5944a53907773 |
14 | 24c7dbcb84325 |
15 | 1060637026011 |
hex | 792a368103ed |
133222210012141 has 2 divisors, whose sum is σ = 133222210012142. Its totient is φ = 133222210012140.
The previous prime is 133222210012091. The next prime is 133222210012147. The reversal of 133222210012141 is 141210012222331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85053196660041 + 48169013352100 = 9222429^2 + 6940390^2 .
It is a cyclic number.
It is not a de Polignac number, because 133222210012141 - 27 = 133222210012013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133222210012147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66611105006070 + 66611105006071.
It is an arithmetic number, because the mean of its divisors is an integer number (66611105006071).
Almost surely, 2133222210012141 is an apocalyptic number.
It is an amenable number.
133222210012141 is a deficient number, since it is larger than the sum of its proper divisors (1).
133222210012141 is an equidigital number, since it uses as much as digits as its factorization.
133222210012141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 133222210012141 its reverse (141210012222331), we get a palindrome (274432222234472).
The spelling of 133222210012141 in words is "one hundred thirty-three trillion, two hundred twenty-two billion, two hundred ten million, twelve thousand, one hundred forty-one".
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