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133223121000439 is a prime number
BaseRepresentation
bin11110010010101001101100…
…110011011001011111110111
3122110201000011100210202200221
4132102221230303121133313
5114430211422434003224
61151201505030515211
740030024063161241
oct3622515463313767
9573630140722627
10133223121000439
11394a3676759a28
1212b37649805b07
135944b6a57a7b2
1424c8067b61091
15106068bec36e4
hex792a6ccd97f7

133223121000439 has 2 divisors, whose sum is σ = 133223121000440. Its totient is φ = 133223121000438.

The previous prime is 133223121000383. The next prime is 133223121000451. The reversal of 133223121000439 is 934000121322331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133223121000439 - 217 = 133223120869367 is a prime.

It is a super-2 number, since 2×1332231210004392 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133223121000479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66611560500219 + 66611560500220.

It is an arithmetic number, because the mean of its divisors is an integer number (66611560500220).

Almost surely, 2133223121000439 is an apocalyptic number.

133223121000439 is a deficient number, since it is larger than the sum of its proper divisors (1).

133223121000439 is an equidigital number, since it uses as much as digits as its factorization.

133223121000439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 34.

The spelling of 133223121000439 in words is "one hundred thirty-three trillion, two hundred twenty-three billion, one hundred twenty-one million, four hundred thirty-nine", and thus it is an aban number.