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13322313120301 is a prime number
BaseRepresentation
bin1100000111011101011110…
…1111011011101000101101
31202011121012220111111210121
43001313113233123220231
53221233044124322201
644200104113204541
72543335224045643
oct301672757335055
952147186444717
1013322313120301
114276a63498589
1215b1b53860751
1375839a47b993
14340b36735193
15181825bc59a1
hexc1dd7bdba2d

13322313120301 has 2 divisors, whose sum is σ = 13322313120302. Its totient is φ = 13322313120300.

The previous prime is 13322313120251. The next prime is 13322313120329. The reversal of 13322313120301 is 10302131322331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12234674796100 + 1087638324201 = 3497810^2 + 1042899^2 .

It is a cyclic number.

It is not a de Polignac number, because 13322313120301 - 211 = 13322313118253 is a prime.

It is a super-3 number, since 3×133223131203013 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13322313160301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661156560150 + 6661156560151.

It is an arithmetic number, because the mean of its divisors is an integer number (6661156560151).

Almost surely, 213322313120301 is an apocalyptic number.

It is an amenable number.

13322313120301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13322313120301 is an equidigital number, since it uses as much as digits as its factorization.

13322313120301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13322313120301 its reverse (10302131322331), we get a palindrome (23624444442632).

The spelling of 13322313120301 in words is "thirteen trillion, three hundred twenty-two billion, three hundred thirteen million, one hundred twenty thousand, three hundred one".