Base | Representation |
---|---|
bin | 11110010010101011100100… |
… | …111010111001111011011111 |
3 | 122110201012100210211020201122 |
4 | 132102223210322321323133 |
5 | 114430230034333443312 |
6 | 1151202441020201155 |
7 | 40030125033321323 |
oct | 3622534472717337 |
9 | 573635323736648 |
10 | 133225136234207 |
11 | 394a4510260986 |
12 | 12b37b106991bb |
13 | 59450cbc29a04 |
14 | 24c81b9663983 |
15 | 1060758d94b72 |
hex | 792ae4eb9edf |
133225136234207 has 2 divisors, whose sum is σ = 133225136234208. Its totient is φ = 133225136234206.
The previous prime is 133225136234119. The next prime is 133225136234221. The reversal of 133225136234207 is 702432631522331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133225136234207 - 240 = 132125624606431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133225136234807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66612568117103 + 66612568117104.
It is an arithmetic number, because the mean of its divisors is an integer number (66612568117104).
Almost surely, 2133225136234207 is an apocalyptic number.
133225136234207 is a deficient number, since it is larger than the sum of its proper divisors (1).
133225136234207 is an equidigital number, since it uses as much as digits as its factorization.
133225136234207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 44.
Adding to 133225136234207 its reverse (702432631522331), we get a palindrome (835657767756538).
The spelling of 133225136234207 in words is "one hundred thirty-three trillion, two hundred twenty-five billion, one hundred thirty-six million, two hundred thirty-four thousand, two hundred seven".
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