Base | Representation |
---|---|
bin | 10011011000110011010… |
… | …010011000110100010111 |
3 | 11201100220022002201110011 |
4 | 103120303102120310113 |
5 | 133312022340220043 |
6 | 2500014511341051 |
7 | 165153433603531 |
oct | 23306322306427 |
9 | 4640808081404 |
10 | 1332300320023 |
11 | 474030885752 |
12 | 196260821787 |
13 | 98834c1723a |
14 | 486ab306851 |
15 | 249c998559d |
hex | 13633498d17 |
1332300320023 has 4 divisors (see below), whose sum is σ = 1336117799800. Its totient is φ = 1328482840248.
The previous prime is 1332300319997. The next prime is 1332300320051. The reversal of 1332300320023 is 3200230032331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1332300320023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1332300319976 and 1332300320003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1332300320053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1908739365 + ... + 1908740062.
It is an arithmetic number, because the mean of its divisors is an integer number (334029449950).
Almost surely, 21332300320023 is an apocalyptic number.
1332300320023 is a deficient number, since it is larger than the sum of its proper divisors (3817479777).
1332300320023 is an equidigital number, since it uses as much as digits as its factorization.
1332300320023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3817479776.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 1332300320023 its reverse (3200230032331), we get a palindrome (4532530352354).
The spelling of 1332300320023 in words is "one trillion, three hundred thirty-two billion, three hundred million, three hundred twenty thousand, twenty-three".
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