Base | Representation |
---|---|
bin | 10011011000110011010… |
… | …101110010010101110101 |
3 | 11201100220100202222122012 |
4 | 103120303111302111311 |
5 | 133312023102222442 |
6 | 2500014542414005 |
7 | 165153444304241 |
oct | 23306325622565 |
9 | 4640810688565 |
10 | 1332301210997 |
11 | 474031334099 |
12 | 196260b91305 |
13 | 98835169943 |
14 | 486ab499421 |
15 | 249c9aae582 |
hex | 13633572575 |
1332301210997 has 2 divisors, whose sum is σ = 1332301210998. Its totient is φ = 1332301210996.
The previous prime is 1332301210993. The next prime is 1332301211069. The reversal of 1332301210997 is 7990121032331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1325834799601 + 6466411396 = 1151449^2 + 80414^2 .
It is a cyclic number.
It is not a de Polignac number, because 1332301210997 - 22 = 1332301210993 is a prime.
It is a super-3 number, since 3×13323012109973 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1332301210993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666150605498 + 666150605499.
It is an arithmetic number, because the mean of its divisors is an integer number (666150605499).
Almost surely, 21332301210997 is an apocalyptic number.
It is an amenable number.
1332301210997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332301210997 is an equidigital number, since it uses as much as digits as its factorization.
1332301210997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 41.
The spelling of 1332301210997 in words is "one trillion, three hundred thirty-two billion, three hundred one million, two hundred ten thousand, nine hundred ninety-seven".
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