Base | Representation |
---|---|
bin | 11110010010110001001001… |
… | …101101111110001101011111 |
3 | 122110201202210222200101221212 |
4 | 132102301021231332031133 |
5 | 114430324314302404413 |
6 | 1151205311014415035 |
7 | 40030426261164305 |
oct | 3622611155761537 |
9 | 573652728611855 |
10 | 133231122309983 |
11 | 394a7002241245 |
12 | 12b3910136147b |
13 | 594584415b999 |
14 | 24c85c668a275 |
15 | 10609a967bca8 |
hex | 792c49b7e35f |
133231122309983 has 2 divisors, whose sum is σ = 133231122309984. Its totient is φ = 133231122309982.
The previous prime is 133231122309979. The next prime is 133231122310009. The reversal of 133231122309983 is 389903221132331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133231122309983 - 22 = 133231122309979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133231122309913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66615561154991 + 66615561154992.
It is an arithmetic number, because the mean of its divisors is an integer number (66615561154992).
Almost surely, 2133231122309983 is an apocalyptic number.
133231122309983 is a deficient number, since it is larger than the sum of its proper divisors (1).
133231122309983 is an equidigital number, since it uses as much as digits as its factorization.
133231122309983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1259712, while the sum is 50.
The spelling of 133231122309983 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, one hundred twenty-two million, three hundred nine thousand, nine hundred eighty-three".
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