Base | Representation |
---|---|
bin | 1100000111100000011101… |
… | …1000000011110111110101 |
3 | 1202011200021121022001021111 |
4 | 3001320013120003313311 |
5 | 3221241213222100041 |
6 | 44200315302315021 |
7 | 2543364100004656 |
oct | 301700730036765 |
9 | 52150247261244 |
10 | 13323112300021 |
11 | 4277333619097 |
12 | 15b2137428a71 |
13 | 758496c053a4 |
14 | 340bb092952d |
15 | 181870e39981 |
hex | c1e07603df5 |
13323112300021 has 4 divisors (see below), whose sum is σ = 13325170565772. Its totient is φ = 13321054034272.
The previous prime is 13323112300019. The next prime is 13323112300171. The reversal of 13323112300021 is 12000321132331.
13323112300021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8135586767025 + 5187525532996 = 2852295^2 + 2277614^2 .
It is a cyclic number.
It is not a de Polignac number, because 13323112300021 - 21 = 13323112300019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13323112299965 and 13323112300001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13323112301021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1029123166 + ... + 1029136111.
It is an arithmetic number, because the mean of its divisors is an integer number (3331292641443).
Almost surely, 213323112300021 is an apocalyptic number.
It is an amenable number.
13323112300021 is a deficient number, since it is larger than the sum of its proper divisors (2058265751).
13323112300021 is an equidigital number, since it uses as much as digits as its factorization.
13323112300021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2058265750.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13323112300021 its reverse (12000321132331), we get a palindrome (25323433432352).
The spelling of 13323112300021 in words is "thirteen trillion, three hundred twenty-three billion, one hundred twelve million, three hundred thousand, twenty-one".
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