Base | Representation |
---|---|
bin | 11000110100001111… |
… | …11101111011001101 |
3 | 1021101111221120222121 |
4 | 30122013331323031 |
5 | 204241214320112 |
6 | 10042014212541 |
7 | 651106213213 |
oct | 143207757315 |
9 | 37344846877 |
10 | 13323198157 |
11 | 5717663a75 |
12 | 26b9ab4151 |
13 | 1344332809 |
14 | 90565acb3 |
15 | 52e9e4407 |
hex | 31a1fdecd |
13323198157 has 2 divisors, whose sum is σ = 13323198158. Its totient is φ = 13323198156.
The previous prime is 13323198151. The next prime is 13323198167. The reversal of 13323198157 is 75189132331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13301239561 + 21958596 = 115331^2 + 4686^2 .
It is a cyclic number.
It is not a de Polignac number, because 13323198157 - 23 = 13323198149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13323198151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661599078 + 6661599079.
It is an arithmetic number, because the mean of its divisors is an integer number (6661599079).
Almost surely, 213323198157 is an apocalyptic number.
It is an amenable number.
13323198157 is a deficient number, since it is larger than the sum of its proper divisors (1).
13323198157 is an equidigital number, since it uses as much as digits as its factorization.
13323198157 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 136080, while the sum is 43.
The spelling of 13323198157 in words is "thirteen billion, three hundred twenty-three million, one hundred ninety-eight thousand, one hundred fifty-seven".
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