Base | Representation |
---|---|
bin | 11000110100010001… |
… | …11001000000101101 |
3 | 1021101112101212222011 |
4 | 30122020321000231 |
5 | 204241300041143 |
6 | 10042023321221 |
7 | 651111241621 |
oct | 143210710055 |
9 | 37345355864 |
10 | 13323440173 |
11 | 571780988a |
12 | 26b9bb0211 |
13 | 13443b8a14 |
14 | 9056c1181 |
15 | 52ea40e9d |
hex | 31a23902d |
13323440173 has 2 divisors, whose sum is σ = 13323440174. Its totient is φ = 13323440172.
The previous prime is 13323440113. The next prime is 13323440189. The reversal of 13323440173 is 37104432331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7127074084 + 6196366089 = 84422^2 + 78717^2 .
It is an emirp because it is prime and its reverse (37104432331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13323440173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13323440113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661720086 + 6661720087.
It is an arithmetic number, because the mean of its divisors is an integer number (6661720087).
Almost surely, 213323440173 is an apocalyptic number.
It is an amenable number.
13323440173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13323440173 is an equidigital number, since it uses as much as digits as its factorization.
13323440173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 31.
The spelling of 13323440173 in words is "thirteen billion, three hundred twenty-three million, four hundred forty thousand, one hundred seventy-three".
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