Base | Representation |
---|---|
bin | 11110010010110100001111… |
… | …101110110010000011100111 |
3 | 122110202002101111210121222101 |
4 | 132102310033232302003213 |
5 | 114430403120232123421 |
6 | 1151211020410512531 |
7 | 40030604510446321 |
oct | 3622641756620347 |
9 | 573662344717871 |
10 | 133234444411111 |
11 | 394a8457500a6a |
12 | 12b39889a35747 |
13 | 5945c534ab8b4 |
14 | 24c881d97a611 |
15 | 1060b01148191 |
hex | 792d0fbb20e7 |
133234444411111 has 4 divisors (see below), whose sum is σ = 133234468586824. Its totient is φ = 133234420235400.
The previous prime is 133234444411097. The next prime is 133234444411151. The reversal of 133234444411111 is 111114444432331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133234444411111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133234444411151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660241 + ... + 16337221.
It is an arithmetic number, because the mean of its divisors is an integer number (33308617146706).
Almost surely, 2133234444411111 is an apocalyptic number.
133234444411111 is a deficient number, since it is larger than the sum of its proper divisors (24175713).
133234444411111 is an equidigital number, since it uses as much as digits as its factorization.
133234444411111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24175712.
The product of its digits is 55296, while the sum is 37.
Adding to 133234444411111 its reverse (111114444432331), we get a palindrome (244348888843442).
The spelling of 133234444411111 in words is "one hundred thirty-three trillion, two hundred thirty-four billion, four hundred forty-four million, four hundred eleven thousand, one hundred eleven".
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