Base | Representation |
---|---|
bin | 10011011000110101111… |
… | …110111001001001111101 |
3 | 11201101000110012012022020 |
4 | 103120311332321021331 |
5 | 133312120424304440 |
6 | 2500023204510353 |
7 | 165154523146035 |
oct | 23306576711175 |
9 | 4641013165266 |
10 | 1332345541245 |
11 | 474054362064 |
12 | 1962739ab3b9 |
13 | 988413bb464 |
14 | 486b33188c5 |
15 | 249cd9193d0 |
hex | 13635fb927d |
1332345541245 has 32 divisors (see below), whose sum is σ = 2136685187712. Its totient is φ = 708941279232.
The previous prime is 1332345541243. The next prime is 1332345541259. The reversal of 1332345541245 is 5421455432331.
It is not a de Polignac number, because 1332345541245 - 21 = 1332345541243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1332345541197 and 1332345541206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1332345541243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20309337 + ... + 20374833.
It is an arithmetic number, because the mean of its divisors is an integer number (66771412116).
Almost surely, 21332345541245 is an apocalyptic number.
1332345541245 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1332345541245 is a deficient number, since it is larger than the sum of its proper divisors (804339646467).
1332345541245 is a wasteful number, since it uses less digits than its factorization.
1332345541245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68621.
The product of its digits is 864000, while the sum is 42.
The spelling of 1332345541245 in words is "one trillion, three hundred thirty-two billion, three hundred forty-five million, five hundred forty-one thousand, two hundred forty-five".
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