Search a number
-
+
1332412200061 is a prime number
BaseRepresentation
bin10011011000111001111…
…101001011010001111101
311201101012002121211000021
4103120321331023101331
5133312240010400221
62500033545332141
7165156262555435
oct23307175132175
94641162554007
101332412200061
11474088a50898
12196292197051
139885215a247
14486bc10b2c5
15249d46d5041
hex13639f4b47d

1332412200061 has 2 divisors, whose sum is σ = 1332412200062. Its totient is φ = 1332412200060.

The previous prime is 1332412200001. The next prime is 1332412200073. The reversal of 1332412200061 is 1600022142331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 999812008836 + 332600191225 = 999906^2 + 576715^2 .

It is an emirp because it is prime and its reverse (1600022142331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1332412200061 - 225 = 1332378645629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1332412199999 and 1332412200035.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332412200001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666206100030 + 666206100031.

It is an arithmetic number, because the mean of its divisors is an integer number (666206100031).

Almost surely, 21332412200061 is an apocalyptic number.

It is an amenable number.

1332412200061 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332412200061 is an equidigital number, since it uses as much as digits as its factorization.

1332412200061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1332412200061 its reverse (1600022142331), we get a palindrome (2932434342392).

The spelling of 1332412200061 in words is "one trillion, three hundred thirty-two billion, four hundred twelve million, two hundred thousand, sixty-one".