1332413043001 has 4 divisors (see below), whose sum is σ = 1334779674192. Its totient is φ = 1330046411812.

The previous prime is 1332413042969. The next prime is 1332413043023. The reversal of 1332413043001 is 1003403142331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332413043001 - 2⁵ = 1332413042969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1332413047001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1183314751 + ... + 1183315876.

It is an arithmetic number, because the mean of its divisors is an integer number (333694918548).

Almost surely, 2^{1332413043001} is an apocalyptic number.

It is an amenable number.

1332413043001 is a deficient number, since it is larger than the sum of its proper divisors (2366631191).

1332413043001 is an equidigital number, since it uses as much as digits as its factorization.

1332413043001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2366631190.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1332413043001 its reverse (1003403142331), we get a palindrome (2335816185332).

The spelling of 1332413043001 in words is "one trillion, three hundred thirty-two billion, four hundred thirteen million, forty-three thousand, one".