Base | Representation |
---|---|
bin | 111110000010111011… |
… | …0000000111111000111 |
3 | 110201220212101112112201 |
4 | 1330011312000333013 |
5 | 4140334430011241 |
6 | 141113251055331 |
7 | 12424601404621 |
oct | 1740566007707 |
9 | 421825345481 |
10 | 133242032071 |
11 | 51564720885 |
12 | 219a65a1547 |
13 | c74576bac5 |
14 | 663dcb5c11 |
15 | 36ec7b5931 |
hex | 1f05d80fc7 |
133242032071 has 2 divisors, whose sum is σ = 133242032072. Its totient is φ = 133242032070.
The previous prime is 133242031933. The next prime is 133242032083. The reversal of 133242032071 is 170230242331.
It is a strong prime.
It is an emirp because it is prime and its reverse (170230242331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133242032071 - 219 = 133241507783 is a prime.
It is a super-2 number, since 2×1332420320712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133242032471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66621016035 + 66621016036.
It is an arithmetic number, because the mean of its divisors is an integer number (66621016036).
Almost surely, 2133242032071 is an apocalyptic number.
133242032071 is a deficient number, since it is larger than the sum of its proper divisors (1).
133242032071 is an equidigital number, since it uses as much as digits as its factorization.
133242032071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
The spelling of 133242032071 in words is "one hundred thirty-three billion, two hundred forty-two million, thirty-two thousand, seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.245 sec. • engine limits •