Base | Representation |
---|---|
bin | 111110000010111101… |
… | …1000000010100010111 |
3 | 110201220221211222202120 |
4 | 1330011323000110113 |
5 | 4140340243340210 |
6 | 141113335111023 |
7 | 12424615463160 |
oct | 1740573002427 |
9 | 421827758676 |
10 | 133243340055 |
11 | 51565434561 |
12 | 219a6b12473 |
13 | c745b09267 |
14 | 6640136767 |
15 | 36ec973270 |
hex | 1f05ec0517 |
133243340055 has 32 divisors (see below), whose sum is σ = 243672841728. Its totient is φ = 60904272000.
The previous prime is 133243340033. The next prime is 133243340063. The reversal of 133243340055 is 550043342331.
It is not a de Polignac number, because 133243340055 - 28 = 133243339799 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133243339998 and 133243340025.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 912880 + ... + 1048730.
It is an arithmetic number, because the mean of its divisors is an integer number (7614776304).
Almost surely, 2133243340055 is an apocalyptic number.
133243340055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133243340055 is a deficient number, since it is larger than the sum of its proper divisors (110429501673).
133243340055 is a wasteful number, since it uses less digits than its factorization.
133243340055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145207.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 133243340055 its reverse (550043342331), we get a palindrome (683286682386).
The spelling of 133243340055 in words is "one hundred thirty-three billion, two hundred forty-three million, three hundred forty thousand, fifty-five".
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