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133243340055 = 3579341135851
BaseRepresentation
bin111110000010111101…
…1000000010100010111
3110201220221211222202120
41330011323000110113
54140340243340210
6141113335111023
712424615463160
oct1740573002427
9421827758676
10133243340055
1151565434561
12219a6b12473
13c745b09267
146640136767
1536ec973270
hex1f05ec0517

133243340055 has 32 divisors (see below), whose sum is σ = 243672841728. Its totient is φ = 60904272000.

The previous prime is 133243340033. The next prime is 133243340063. The reversal of 133243340055 is 550043342331.

It is not a de Polignac number, because 133243340055 - 28 = 133243339799 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133243339998 and 133243340025.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 912880 + ... + 1048730.

It is an arithmetic number, because the mean of its divisors is an integer number (7614776304).

Almost surely, 2133243340055 is an apocalyptic number.

133243340055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

133243340055 is a deficient number, since it is larger than the sum of its proper divisors (110429501673).

133243340055 is a wasteful number, since it uses less digits than its factorization.

133243340055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145207.

The product of its (nonzero) digits is 64800, while the sum is 33.

Adding to 133243340055 its reverse (550043342331), we get a palindrome (683286682386).

The spelling of 133243340055 in words is "one hundred thirty-three billion, two hundred forty-three million, three hundred forty thousand, fifty-five".

Divisors: 1 3 5 7 15 21 35 105 9341 28023 46705 65387 135851 140115 196161 326935 407553 679255 950957 980805 2037765 2852871 4754785 14264355 1268984191 3806952573 6344920955 8882889337 19034762865 26648668011 44414446685 133243340055