Base | Representation |
---|---|
bin | 11110010010111100100101… |
… | …101101100011110110101111 |
3 | 122110202221111212012101220202 |
4 | 132102330211231203312233 |
5 | 114431024442144433033 |
6 | 1151215101355104115 |
7 | 40031342512322234 |
oct | 3622744555436657 |
9 | 573687455171822 |
10 | 133243403124143 |
11 | 39501234462734 |
12 | 12b3b56a14203b |
13 | 5946a50534620 |
14 | 24c902d6c578b |
15 | 1060e778bb8e8 |
hex | 792f25b63daf |
133243403124143 has 16 divisors (see below), whose sum is σ = 145469421585600. Its totient is φ = 121299997319424.
The previous prime is 133243403124121. The next prime is 133243403124157. The reversal of 133243403124143 is 341421304342331.
It is a cyclic number.
It is not a de Polignac number, because 133243403124143 - 210 = 133243403123119 is a prime.
It is a super-2 number, since 2×1332434031241432 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133243403124097 and 133243403124106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133243405124143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7476305 + ... + 17954997.
It is an arithmetic number, because the mean of its divisors is an integer number (9091838849100).
Almost surely, 2133243403124143 is an apocalyptic number.
133243403124143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133243403124143 is a deficient number, since it is larger than the sum of its proper divisors (12226018461457).
133243403124143 is a wasteful number, since it uses less digits than its factorization.
133243403124143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10492178.
The product of its (nonzero) digits is 248832, while the sum is 38.
Adding to 133243403124143 its reverse (341421304342331), we get a palindrome (474664707466474).
The spelling of 133243403124143 in words is "one hundred thirty-three trillion, two hundred forty-three billion, four hundred three million, one hundred twenty-four thousand, one hundred forty-three".
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