Base | Representation |
---|---|
bin | 1100000111100101011000… |
… | …0110100100010110000001 |
3 | 1202011210200122122101010011 |
4 | 3001321112012210112001 |
5 | 3221301414334130442 |
6 | 44201054324104521 |
7 | 2543441605516021 |
oct | 301712606442601 |
9 | 52153618571104 |
10 | 13324433114497 |
11 | 42779511425aa |
12 | 15b2445835141 |
13 | 75864774a40b |
14 | 340c98107a81 |
15 | 1818ebd8c117 |
hex | c1e561a4581 |
13324433114497 has 2 divisors, whose sum is σ = 13324433114498. Its totient is φ = 13324433114496.
The previous prime is 13324433114437. The next prime is 13324433114501. The reversal of 13324433114497 is 79441133442331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8627607923841 + 4696825190656 = 2937279^2 + 2167216^2 .
It is a cyclic number.
It is not a de Polignac number, because 13324433114497 - 211 = 13324433112449 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13324433114497.
It is not a weakly prime, because it can be changed into another prime (13324433114437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662216557248 + 6662216557249.
It is an arithmetic number, because the mean of its divisors is an integer number (6662216557249).
Almost surely, 213324433114497 is an apocalyptic number.
It is an amenable number.
13324433114497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324433114497 is an equidigital number, since it uses as much as digits as its factorization.
13324433114497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2612736, while the sum is 49.
The spelling of 13324433114497 in words is "thirteen trillion, three hundred twenty-four billion, four hundred thirty-three million, one hundred fourteen thousand, four hundred ninety-seven".
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