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13324433114501 is a prime number
BaseRepresentation
bin1100000111100101011000…
…0110100100010110000101
31202011210200122122101010022
43001321112012210112011
53221301414334131001
644201054324104525
72543441605516025
oct301712606442605
952153618571108
1013324433114501
114277951142603
1215b2445835145
1375864774a412
14340c98107a85
151818ebd8c11b
hexc1e561a4585

13324433114501 has 2 divisors, whose sum is σ = 13324433114502. Its totient is φ = 13324433114500.

The previous prime is 13324433114497. The next prime is 13324433114593. The reversal of 13324433114501 is 10541133442331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12320619485476 + 1003813629025 = 3510074^2 + 1001905^2 .

It is a cyclic number.

It is not a de Polignac number, because 13324433114501 - 22 = 13324433114497 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13324433114701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662216557250 + 6662216557251.

It is an arithmetic number, because the mean of its divisors is an integer number (6662216557251).

Almost surely, 213324433114501 is an apocalyptic number.

It is an amenable number.

13324433114501 is a deficient number, since it is larger than the sum of its proper divisors (1).

13324433114501 is an equidigital number, since it uses as much as digits as its factorization.

13324433114501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 13324433114501 its reverse (10541133442331), we get a palindrome (23865566556832).

The spelling of 13324433114501 in words is "thirteen trillion, three hundred twenty-four billion, four hundred thirty-three million, one hundred fourteen thousand, five hundred one".