Base | Representation |
---|---|
bin | 11000110100011001… |
… | …01101101100110111 |
3 | 1021101121021210210112 |
4 | 30122030231230313 |
5 | 204242024124143 |
6 | 10042101013235 |
7 | 651122614625 |
oct | 143214555467 |
9 | 37347253715 |
10 | 13324442423 |
11 | 5718333896 |
12 | 26ba3b421b |
13 | 1344679c76 |
14 | 9058a2515 |
15 | 52eb8ce18 |
hex | 31a32db37 |
13324442423 has 2 divisors, whose sum is σ = 13324442424. Its totient is φ = 13324442422.
The previous prime is 13324442387. The next prime is 13324442429. The reversal of 13324442423 is 32424442331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13324442423 - 218 = 13324180279 is a prime.
It is a super-2 number, since 2×133244424232 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13324442423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13324442429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662221211 + 6662221212.
It is an arithmetic number, because the mean of its divisors is an integer number (6662221212).
Almost surely, 213324442423 is an apocalyptic number.
13324442423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324442423 is an equidigital number, since it uses as much as digits as its factorization.
13324442423 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 55296, while the sum is 32.
Adding to 13324442423 its reverse (32424442331), we get a palindrome (45748884754).
The spelling of 13324442423 in words is "thirteen billion, three hundred twenty-four million, four hundred forty-two thousand, four hundred twenty-three".
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