Base | Representation |
---|---|
bin | 11000110100011011… |
… | …10001001001011001 |
3 | 1021101121210211202022 |
4 | 30122031301021121 |
5 | 204242111444211 |
6 | 10042110544225 |
7 | 651125145221 |
oct | 143215611131 |
9 | 37347724668 |
10 | 13324718681 |
11 | 57185023aa |
12 | 26ba508075 |
13 | 1344745931 |
14 | 905935081 |
15 | 52ebe4bdb |
hex | 31a371259 |
13324718681 has 2 divisors, whose sum is σ = 13324718682. Its totient is φ = 13324718680.
The previous prime is 13324718663. The next prime is 13324718683. The reversal of 13324718681 is 18681742331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7806606025 + 5518112656 = 88355^2 + 74284^2 .
It is a cyclic number.
It is not a de Polignac number, because 13324718681 - 222 = 13320524377 is a prime.
It is a super-2 number, since 2×133247186812 (a number of 21 digits) contains 22 as substring.
Together with 13324718683, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13324718683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662359340 + 6662359341.
It is an arithmetic number, because the mean of its divisors is an integer number (6662359341).
Almost surely, 213324718681 is an apocalyptic number.
It is an amenable number.
13324718681 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324718681 is an equidigital number, since it uses as much as digits as its factorization.
13324718681 is an evil number, because the sum of its binary digits is even.
The product of its digits is 193536, while the sum is 44.
The spelling of 13324718681 in words is "thirteen billion, three hundred twenty-four million, seven hundred eighteen thousand, six hundred eighty-one".
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