Base | Representation |
---|---|
bin | 11110010011000010111011… |
… | …101011001001001000100111 |
3 | 122110210121002112010210011102 |
4 | 132103002323223021020213 |
5 | 114431132414243240403 |
6 | 1151222145300430315 |
7 | 40032003344210126 |
oct | 3623027353111047 |
9 | 573717075123142 |
10 | 133250214040103 |
11 | 39504109aaa6a6 |
12 | 12b4094b0a839b |
13 | 5947597605a04 |
14 | 24c94b80a1abd |
15 | 10612257d5b88 |
hex | 7930bbac9227 |
133250214040103 has 32 divisors (see below), whose sum is σ = 143925428275200. Its totient is φ = 123036471866880.
The previous prime is 133250214040051. The next prime is 133250214040219. The reversal of 133250214040103 is 301040412052331.
It is a cyclic number.
It is not a de Polignac number, because 133250214040103 - 26 = 133250214040039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133250214049103) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 483355298 + ... + 483630896.
It is an arithmetic number, because the mean of its divisors is an integer number (4497669633600).
Almost surely, 2133250214040103 is an apocalyptic number.
133250214040103 is a deficient number, since it is larger than the sum of its proper divisors (10675214235097).
133250214040103 is a wasteful number, since it uses less digits than its factorization.
133250214040103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280127.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 133250214040103 its reverse (301040412052331), we get a palindrome (434290626092434).
The spelling of 133250214040103 in words is "one hundred thirty-three trillion, two hundred fifty billion, two hundred fourteen million, forty thousand, one hundred three".
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