Base | Representation |
---|---|
bin | 11000110100011110… |
… | …10101100101000010 |
3 | 1021101122120202001012 |
4 | 30122033111211002 |
5 | 204242213130200 |
6 | 10042123440522 |
7 | 651131510441 |
oct | 143217254502 |
9 | 37348522035 |
10 | 13325130050 |
11 | 5718763481 |
12 | 26ba686142 |
13 | 134485ac4b |
14 | 905a00d58 |
15 | 52ec76a35 |
hex | 31a3d5942 |
13325130050 has 48 divisors (see below), whose sum is σ = 25649376192. Its totient is φ = 5146315200.
The previous prime is 13325130041. The next prime is 13325130059. The reversal of 13325130050 is 5003152331.
It is an interprime number because it is at equal distance from previous prime (13325130041) and next prime (13325130059).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13325129998 and 13325130025.
It is not an unprimeable number, because it can be changed into a prime (13325130059) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 214859 + ... + 269841.
It is an arithmetic number, because the mean of its divisors is an integer number (534362004).
Almost surely, 213325130050 is an apocalyptic number.
13325130050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13325130050 is a deficient number, since it is larger than the sum of its proper divisors (12324246142).
13325130050 is a wasteful number, since it uses less digits than its factorization.
13325130050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55163 (or 55158 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 23.
Adding to 13325130050 its reverse (5003152331), we get a palindrome (18328282381).
The spelling of 13325130050 in words is "thirteen billion, three hundred twenty-five million, one hundred thirty thousand, fifty".
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