Base | Representation |
---|---|
bin | 111110000011001110… |
… | …1101110011111110101 |
3 | 110201221120222102102101 |
4 | 1330012131232133311 |
5 | 4140400111121401 |
6 | 141114302142101 |
7 | 12425056032562 |
oct | 1740635563765 |
9 | 421846872371 |
10 | 133252442101 |
11 | 5156a591009 |
12 | 219a9b81931 |
13 | c74797519c |
14 | 6641425869 |
15 | 36ed670101 |
hex | 1f0676e7f5 |
133252442101 has 2 divisors, whose sum is σ = 133252442102. Its totient is φ = 133252442100.
The previous prime is 133252442077. The next prime is 133252442137. The reversal of 133252442101 is 101244252331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 122311072900 + 10941369201 = 349730^2 + 104601^2 .
It is a cyclic number.
It is not a de Polignac number, because 133252442101 - 215 = 133252409333 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133252442101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133252442501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66626221050 + 66626221051.
It is an arithmetic number, because the mean of its divisors is an integer number (66626221051).
Almost surely, 2133252442101 is an apocalyptic number.
It is an amenable number.
133252442101 is a deficient number, since it is larger than the sum of its proper divisors (1).
133252442101 is an equidigital number, since it uses as much as digits as its factorization.
133252442101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 133252442101 its reverse (101244252331), we get a palindrome (234496694432).
The spelling of 133252442101 in words is "one hundred thirty-three billion, two hundred fifty-two million, four hundred forty-two thousand, one hundred one".
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