Base | Representation |
---|---|
bin | 111110000011001110… |
… | …1101110100011011101 |
3 | 110201221120222102201222 |
4 | 1330012131232203131 |
5 | 4140400111123313 |
6 | 141114302143125 |
7 | 12425056033343 |
oct | 1740635564335 |
9 | 421846872658 |
10 | 133252442333 |
11 | 5156a5911aa |
12 | 219a9b81aa5 |
13 | c74797531a |
14 | 6641425993 |
15 | 36ed670208 |
hex | 1f0676e8dd |
133252442333 has 2 divisors, whose sum is σ = 133252442334. Its totient is φ = 133252442332.
The previous prime is 133252442321. The next prime is 133252442381. The reversal of 133252442333 is 333244252331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126663386404 + 6589055929 = 355898^2 + 81173^2 .
It is a cyclic number.
It is not a de Polignac number, because 133252442333 - 28 = 133252442077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133252442293 and 133252442302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133252442933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66626221166 + 66626221167.
It is an arithmetic number, because the mean of its divisors is an integer number (66626221167).
Almost surely, 2133252442333 is an apocalyptic number.
It is an amenable number.
133252442333 is a deficient number, since it is larger than the sum of its proper divisors (1).
133252442333 is an equidigital number, since it uses as much as digits as its factorization.
133252442333 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 35.
Adding to 133252442333 its reverse (333244252331), we get a palindrome (466496694664).
The spelling of 133252442333 in words is "one hundred thirty-three billion, two hundred fifty-two million, four hundred forty-two thousand, three hundred thirty-three".
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