Base | Representation |
---|---|
bin | 11110010011000101000101… |
… | …110110110000011100010111 |
3 | 122110210211002002102122110012 |
4 | 132103011011312300130113 |
5 | 114431202141234344003 |
6 | 1151223211313550435 |
7 | 40032114654351332 |
oct | 3623050566603427 |
9 | 573724062378405 |
10 | 133252532340503 |
11 | 39505099690044 |
12 | 12b4129757541b |
13 | 59478769b77b4 |
14 | 24c9657d35619 |
15 | 106130e0be8d8 |
hex | 793145db0717 |
133252532340503 has 2 divisors, whose sum is σ = 133252532340504. Its totient is φ = 133252532340502.
The previous prime is 133252532340427. The next prime is 133252532340511. The reversal of 133252532340503 is 305043235252331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133252532340503 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133252532340703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66626266170251 + 66626266170252.
It is an arithmetic number, because the mean of its divisors is an integer number (66626266170252).
Almost surely, 2133252532340503 is an apocalyptic number.
133252532340503 is a deficient number, since it is larger than the sum of its proper divisors (1).
133252532340503 is an equidigital number, since it uses as much as digits as its factorization.
133252532340503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 133252532340503 its reverse (305043235252331), we get a palindrome (438295767592834).
The spelling of 133252532340503 in words is "one hundred thirty-three trillion, two hundred fifty-two billion, five hundred thirty-two million, three hundred forty thousand, five hundred three".
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