Base | Representation |
---|---|
bin | 1100000111101001001000… |
… | …1100001010000010000001 |
3 | 1202011220021220120001122220 |
4 | 3001322102030022002001 |
5 | 3221311000422300140 |
6 | 44201342335121253 |
7 | 2543505566305260 |
oct | 301722214120201 |
9 | 52156256501586 |
10 | 13325441212545 |
11 | 4278319197590 |
12 | 15b2687373229 |
13 | 758778561537 |
14 | 340d51d625d7 |
15 | 18195a61cbd0 |
hex | c1e9230a081 |
13325441212545 has 32 divisors (see below), whose sum is σ = 26581659356160. Its totient is φ = 5537845698240.
The previous prime is 13325441212507. The next prime is 13325441212561. The reversal of 13325441212545 is 54521214452331.
It is not a de Polignac number, because 13325441212545 - 27 = 13325441212417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13325441212497 and 13325441212506.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5768588115 + ... + 5768590424.
It is an arithmetic number, because the mean of its divisors is an integer number (830676854880).
Almost surely, 213325441212545 is an apocalyptic number.
13325441212545 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13325441212545 is a deficient number, since it is larger than the sum of its proper divisors (13256218143615).
13325441212545 is a wasteful number, since it uses less digits than its factorization.
13325441212545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11537178565.
The product of its digits is 576000, while the sum is 42.
Adding to 13325441212545 its reverse (54521214452331), we get a palindrome (67846655664876).
The spelling of 13325441212545 in words is "thirteen trillion, three hundred twenty-five billion, four hundred forty-one million, two hundred twelve thousand, five hundred forty-five".
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