Base | Representation |
---|---|
bin | 1100000111101001001001… |
… | …0011000000001100011111 |
3 | 1202011220022000221020112221 |
4 | 3001322102103000030133 |
5 | 3221311001402213023 |
6 | 44201342441410211 |
7 | 2543505620461552 |
oct | 301722223001437 |
9 | 52156260836487 |
10 | 13325443007263 |
11 | 427831a202a22 |
12 | 15b2687a99967 |
13 | 758778a3c3ba |
14 | 340d522ac699 |
15 | 18195a87485d |
hex | c1e924c031f |
13325443007263 has 2 divisors, whose sum is σ = 13325443007264. Its totient is φ = 13325443007262.
The previous prime is 13325443007249. The next prime is 13325443007269. The reversal of 13325443007263 is 36270034452331.
It is a strong prime.
It is an emirp because it is prime and its reverse (36270034452331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13325443007263 - 25 = 13325443007231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13325443007269) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662721503631 + 6662721503632.
It is an arithmetic number, because the mean of its divisors is an integer number (6662721503632).
Almost surely, 213325443007263 is an apocalyptic number.
13325443007263 is a deficient number, since it is larger than the sum of its proper divisors (1).
13325443007263 is an equidigital number, since it uses as much as digits as its factorization.
13325443007263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 43.
Adding to 13325443007263 its reverse (36270034452331), we get a palindrome (49595477459594).
The spelling of 13325443007263 in words is "thirteen trillion, three hundred twenty-five billion, four hundred forty-three million, seven thousand, two hundred sixty-three".
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