Base | Representation |
---|---|
bin | 10011011001000001111… |
… | …000111101001110100010 |
3 | 11201101112101002120210010 |
4 | 103121001320331032202 |
5 | 133313023044433100 |
6 | 2500055102345350 |
7 | 165162500156040 |
oct | 23310170751642 |
9 | 4641471076703 |
10 | 1332545311650 |
11 | 4741470a8573 |
12 | 19630a88b256 |
13 | 988738c50b7 |
14 | 486d1a7b390 |
15 | 249e122a750 |
hex | 13641e3d3a2 |
1332545311650 has 96 divisors (see below), whose sum is σ = 3777285702528. Its totient is φ = 304543756800.
The previous prime is 1332545311639. The next prime is 1332545311681. The reversal of 1332545311650 is 561135452331.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1332545311599 and 1332545311608.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8809054 + ... + 8959046.
It is an arithmetic number, because the mean of its divisors is an integer number (39346726068).
Almost surely, 21332545311650 is an apocalyptic number.
1332545311650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1332545311650 is an abundant number, since it is smaller than the sum of its proper divisors (2444740390878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1332545311650 is a wasteful number, since it uses less digits than its factorization.
1332545311650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158476 (or 158471 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 1332545311650 in words is "one trillion, three hundred thirty-two billion, five hundred forty-five million, three hundred eleven thousand, six hundred fifty".
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