Base | Representation |
---|---|
bin | 111110000011101001… |
… | …1010101011000000101 |
3 | 110201222120102101100102 |
4 | 1330013103111120011 |
5 | 4140412210314411 |
6 | 141115523253445 |
7 | 12425316342224 |
oct | 1740723253005 |
9 | 421876371312 |
10 | 133266494981 |
11 | 5157750a164 |
12 | 219b281a285 |
13 | c74a8556b9 |
14 | 6643242cbb |
15 | 36ee9e8d3b |
hex | 1f074d5605 |
133266494981 has 2 divisors, whose sum is σ = 133266494982. Its totient is φ = 133266494980.
The previous prime is 133266494971. The next prime is 133266494987. The reversal of 133266494981 is 189494662331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97834456225 + 35432038756 = 312785^2 + 188234^2 .
It is a cyclic number.
It is not a de Polignac number, because 133266494981 - 218 = 133266232837 is a prime.
It is a super-2 number, since 2×1332664949812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133266494987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66633247490 + 66633247491.
It is an arithmetic number, because the mean of its divisors is an integer number (66633247491).
Almost surely, 2133266494981 is an apocalyptic number.
It is an amenable number.
133266494981 is a deficient number, since it is larger than the sum of its proper divisors (1).
133266494981 is an equidigital number, since it uses as much as digits as its factorization.
133266494981 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6718464, while the sum is 56.
The spelling of 133266494981 in words is "one hundred thirty-three billion, two hundred sixty-six million, four hundred ninety-four thousand, nine hundred eighty-one".
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