13327020391081 has 2 divisors, whose sum is σ = 13327020391082. Its totient is φ = 13327020391080.

The previous prime is 13327020391079. The next prime is 13327020391123. The reversal of 13327020391081 is 18019302072331.

13327020391081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12065487078681 + 1261533312400 = 3473541^2 + 1123180^2 .

It is a cyclic number.

It is not a de Polignac number, because 13327020391081 - 2¹ = 13327020391079 is a prime.

It is a super-2 number, since 2×13327020391081² (a number of 27 digits) contains 22 as substring.

Together with 13327020391079, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13327020397081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6663510195540 + 6663510195541.

It is an arithmetic number, because the mean of its divisors is an integer number (6663510195541).

Almost surely, 2^{13327020391081} is an apocalyptic number.

It is an amenable number.

13327020391081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13327020391081 is an equidigital number, since it uses as much as digits as its factorization.

13327020391081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 40.

The spelling of 13327020391081 in words is "thirteen trillion, three hundred twenty-seven billion, twenty million, three hundred ninety-one thousand, eighty-one".