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13329123881 is a prime number
BaseRepresentation
bin11000110100111101…
…00100101000101001
31021101221002122112212
430122132210220221
5204244223431011
610042345214505
7651210453323
oct143236445051
937357078485
1013329123881
11571aa41067
1226bba91435
131345628a68
14906360613
155302b508b
hex31a7a4a29

13329123881 has 2 divisors, whose sum is σ = 13329123882. Its totient is φ = 13329123880.

The previous prime is 13329123839. The next prime is 13329123883. The reversal of 13329123881 is 18832192331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12967515625 + 361608256 = 113875^2 + 19016^2 .

It is an emirp because it is prime and its reverse (18832192331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13329123881 - 214 = 13329107497 is a prime.

It is a super-3 number, since 3×133291238813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13329123883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13329123883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6664561940 + 6664561941.

It is an arithmetic number, because the mean of its divisors is an integer number (6664561941).

Almost surely, 213329123881 is an apocalyptic number.

It is an amenable number.

13329123881 is a deficient number, since it is larger than the sum of its proper divisors (1).

13329123881 is an equidigital number, since it uses as much as digits as its factorization.

13329123881 is an evil number, because the sum of its binary digits is even.

The product of its digits is 62208, while the sum is 41.

The spelling of 13329123881 in words is "thirteen billion, three hundred twenty-nine million, one hundred twenty-three thousand, eight hundred eighty-one".