Base | Representation |
---|---|
bin | 10011011001011101100… |
… | …110011110101101111101 |
3 | 11201102201202220220001111 |
4 | 103121131212132231331 |
5 | 133320001104331031 |
6 | 2500213151242021 |
7 | 165210144001402 |
oct | 23313546365575 |
9 | 4642652826044 |
10 | 1333010230141 |
11 | 474365583727 |
12 | 19641a519311 |
13 | 989190162b5 |
14 | 487377002a9 |
15 | 24a1be641b1 |
hex | 1365d99eb7d |
1333010230141 has 2 divisors, whose sum is σ = 1333010230142. Its totient is φ = 1333010230140.
The previous prime is 1333010230091. The next prime is 1333010230151. The reversal of 1333010230141 is 1410320103331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1284717970116 + 48292260025 = 1133454^2 + 219755^2 .
It is a cyclic number.
It is not a de Polignac number, because 1333010230141 - 211 = 1333010228093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1333010230151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666505115070 + 666505115071.
It is an arithmetic number, because the mean of its divisors is an integer number (666505115071).
Almost surely, 21333010230141 is an apocalyptic number.
It is an amenable number.
1333010230141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333010230141 is an equidigital number, since it uses as much as digits as its factorization.
1333010230141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1333010230141 its reverse (1410320103331), we get a palindrome (2743330333472).
The spelling of 1333010230141 in words is "one trillion, three hundred thirty-three billion, ten million, two hundred thirty thousand, one hundred forty-one".
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