13330113122333 has 4 divisors (see below), whose sum is σ = 15234414996960. Its totient is φ = 11425811247708.

The previous prime is 13330113122299. The next prime is 13330113122351. The reversal of 13330113122333 is 33322131103331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13330113122333 - 2³² = 13325818155037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13330113122296 and 13330113122305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13330113122383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 952150937303 + ... + 952150937316.

It is an arithmetic number, because the mean of its divisors is an integer number (3808603749240).

Almost surely, 2^{13330113122333} is an apocalyptic number.

It is an amenable number.

13330113122333 is a deficient number, since it is larger than the sum of its proper divisors (1904301874627).

13330113122333 is an equidigital number, since it uses as much as digits as its factorization.

13330113122333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1904301874626.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 13330113122333 its reverse (33322131103331), we get a palindrome (46652244225664).

The spelling of 13330113122333 in words is "thirteen trillion, three hundred thirty billion, one hundred thirteen million, one hundred twenty-two thousand, three hundred thirty-three".