Base | Representation |
---|---|
bin | 10011011001011110001… |
… | …111111101010000001001 |
3 | 11201102202112101021222011 |
4 | 103121132033331100021 |
5 | 133320011400244423 |
6 | 2500214220255521 |
7 | 165210335265130 |
oct | 23313617752011 |
9 | 4642675337864 |
10 | 1333021103113 |
11 | 47437072a757 |
12 | 1964220a15a1 |
13 | 9891b3522cb |
14 | 48738d30917 |
15 | 24a1cdb0b0d |
hex | 1365e3fd409 |
1333021103113 has 12 divisors (see below), whose sum is σ = 1607854503360. Its totient is φ = 1082453224536.
The previous prime is 1333021103111. The next prime is 1333021103129. The reversal of 1333021103113 is 3113011203331.
It is not a de Polignac number, because 1333021103113 - 21 = 1333021103111 is a prime.
It is a super-2 number, since 2×13330211031132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1333021103111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 263753133 + ... + 263758186.
It is an arithmetic number, because the mean of its divisors is an integer number (133987875280).
Almost surely, 21333021103113 is an apocalyptic number.
It is an amenable number.
1333021103113 is a deficient number, since it is larger than the sum of its proper divisors (274833400247).
1333021103113 is an equidigital number, since it uses as much as digits as its factorization.
1333021103113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 527511364 (or 527511345 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1333021103113 its reverse (3113011203331), we get a palindrome (4446032306444).
The spelling of 1333021103113 in words is "one trillion, three hundred thirty-three billion, twenty-one million, one hundred three thousand, one hundred thirteen".
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