Base | Representation |
---|---|
bin | 10011011001011110010… |
… | …011011011001011100010 |
3 | 11201102202121002110220110 |
4 | 103121132103123023202 |
5 | 133320012113342010 |
6 | 2500214251552150 |
7 | 165210346102254 |
oct | 23313623331342 |
9 | 4642677073813 |
10 | 1333022012130 |
11 | 4743711a0706 |
12 | 19642245b656 |
13 | 9891b5acca3 |
14 | 487390c9cd4 |
15 | 24a1cee0120 |
hex | 1365e4db2e2 |
1333022012130 has 64 divisors (see below), whose sum is σ = 3445951703040. Its totient is φ = 328931741376.
The previous prime is 1333022012099. The next prime is 1333022012159. The reversal of 1333022012130 is 312102203331.
It is a super-2 number, since 2×13330220121302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1333022012097 and 1333022012106.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27168922 + ... + 27217941.
It is an arithmetic number, because the mean of its divisors is an integer number (53842995360).
Almost surely, 21333022012130 is an apocalyptic number.
1333022012130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1333022012130 is an abundant number, since it is smaller than the sum of its proper divisors (2112929690910).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1333022012130 is a wasteful number, since it uses less digits than its factorization.
1333022012130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54386935.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1333022012130 its reverse (312102203331), we get a palindrome (1645124215461).
The spelling of 1333022012130 in words is "one trillion, three hundred thirty-three billion, twenty-two million, twelve thousand, one hundred thirty".
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