Base | Representation |
---|---|
bin | 1100000111111010111110… |
… | …1111100111011000000111 |
3 | 1202012100122210022000020112 |
4 | 3001332233233213120013 |
5 | 3221400303343424333 |
6 | 44203453554423235 |
7 | 2544035401405406 |
oct | 301765757473007 |
9 | 52170583260215 |
10 | 13330232014343 |
11 | 427a3574a9912 |
12 | 15b35a3891b1b |
13 | 75905cc651ba |
14 | 34128832963d |
15 | 181b3aeee948 |
hex | c1fafbe7607 |
13330232014343 has 4 divisors (see below), whose sum is σ = 13330530201168. Its totient is φ = 13329933827520.
The previous prime is 13330232014339. The next prime is 13330232014349. The reversal of 13330232014343 is 34341023203331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13330232014343 - 22 = 13330232014339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330232014349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149026346 + ... + 149115767.
It is an arithmetic number, because the mean of its divisors is an integer number (3332632550292).
Almost surely, 213330232014343 is an apocalyptic number.
13330232014343 is a deficient number, since it is larger than the sum of its proper divisors (298186825).
13330232014343 is an equidigital number, since it uses as much as digits as its factorization.
13330232014343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 298186824.
The product of its (nonzero) digits is 46656, while the sum is 32.
Adding to 13330232014343 its reverse (34341023203331), we get a palindrome (47671255217674).
The spelling of 13330232014343 in words is "thirteen trillion, three hundred thirty billion, two hundred thirty-two million, fourteen thousand, three hundred forty-three".
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