Base | Representation |
---|---|
bin | 1100000111111011000001… |
… | …0110110111000111100011 |
3 | 1202012100200111122200211222 |
4 | 3001332300112313013203 |
5 | 3221400314012134220 |
6 | 44203455003125255 |
7 | 2544035555015012 |
oct | 301766026670743 |
9 | 52170614580758 |
10 | 13330242302435 |
11 | 427a362296473 |
12 | 15b35a721382b |
13 | 759062127c26 |
14 | 341289846a79 |
15 | 181b3bd82e25 |
hex | c1fb05b71e3 |
13330242302435 has 64 divisors (see below), whose sum is σ = 16873412282496. Its totient is φ = 10099637452800.
The previous prime is 13330242302383. The next prime is 13330242302467. The reversal of 13330242302435 is 53420324203331.
It is not a de Polignac number, because 13330242302435 - 220 = 13330241253859 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13330242302395 and 13330242302404.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1072159979 + ... + 1072172411.
It is an arithmetic number, because the mean of its divisors is an integer number (263647066914).
Almost surely, 213330242302435 is an apocalyptic number.
13330242302435 is a deficient number, since it is larger than the sum of its proper divisors (3543169980061).
13330242302435 is a wasteful number, since it uses less digits than its factorization.
13330242302435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13656.
The product of its (nonzero) digits is 155520, while the sum is 35.
Adding to 13330242302435 its reverse (53420324203331), we get a palindrome (66750566505766).
The spelling of 13330242302435 in words is "thirteen trillion, three hundred thirty billion, two hundred forty-two million, three hundred two thousand, four hundred thirty-five".
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