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133310301113 = 1112119118283
BaseRepresentation
bin111110000100111101…
…0011100001110111001
3110202002121211222001202
41330021322130032321
54141004414113423
6141124130223545
712426360602003
oct1741172341671
9422077758052
10133310301113
115159a20a380
1221a05424bb5
13c7569527a2
146648da7373
15370379d728
hex1f09e9c3b9

133310301113 has 4 divisors (see below), whose sum is σ = 145429419408. Its totient is φ = 121191182820.

The previous prime is 133310301077. The next prime is 133310301121. The reversal of 133310301113 is 311103013331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311103013331 = 1128282092121.

It is a cyclic number.

It is not a de Polignac number, because 133310301113 - 26 = 133310301049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133310301613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6059559131 + ... + 6059559152.

It is an arithmetic number, because the mean of its divisors is an integer number (36357354852).

Almost surely, 2133310301113 is an apocalyptic number.

It is an amenable number.

133310301113 is a deficient number, since it is larger than the sum of its proper divisors (12119118295).

133310301113 is a wasteful number, since it uses less digits than its factorization.

133310301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12119118294.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 133310301113 its reverse (311103013331), we get a palindrome (444413314444).

The spelling of 133310301113 in words is "one hundred thirty-three billion, three hundred ten million, three hundred one thousand, one hundred thirteen".

Divisors: 1 11 12119118283 133310301113