Base | Representation |
---|---|
bin | 11110010011111010111010… |
… | …110111011110111100101111 |
3 | 122111000100021010000000000020 |
4 | 132103322322313132330233 |
5 | 114433124023442240421 |
6 | 1151305530431133223 |
7 | 40036232152606230 |
oct | 3623727267367457 |
9 | 574010233000006 |
10 | 133310330040111 |
11 | 39527658a07234 |
12 | 12b50527974213 |
13 | 59501580b9253 |
14 | 24cc37c10d087 |
15 | 1062a932eddc6 |
hex | 793ebaddef2f |
133310330040111 has 8 divisors (see below), whose sum is σ = 203139550537344. Its totient is φ = 76177331451480.
The previous prime is 133310330040101. The next prime is 133310330040137. The reversal of 133310330040111 is 111040033013331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133310330040111 - 29 = 133310330039599 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133310330040101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3174055477125 + ... + 3174055477166.
It is an arithmetic number, because the mean of its divisors is an integer number (25392443817168).
Almost surely, 2133310330040111 is an apocalyptic number.
133310330040111 is a deficient number, since it is larger than the sum of its proper divisors (69829220497233).
133310330040111 is an equidigital number, since it uses as much as digits as its factorization.
133310330040111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6348110954301.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 133310330040111 its reverse (111040033013331), we get a palindrome (244350363053442).
The spelling of 133310330040111 in words is "one hundred thirty-three trillion, three hundred ten billion, three hundred thirty million, forty thousand, one hundred eleven".
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