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133310411149 is a prime number
BaseRepresentation
bin111110000100111101…
…0110111000110001101
3110202002122001120000011
41330021322313012031
54141004431124044
6141124132433221
712426361540546
oct1741172670615
9422078046004
10133310411149
115159a285013
1221a05478811
13c7569908b6
146648dd54cd
1537037c1134
hex1f09eb718d

133310411149 has 2 divisors, whose sum is σ = 133310411150. Its totient is φ = 133310411148.

The previous prime is 133310411123. The next prime is 133310411173. The reversal of 133310411149 is 941114013331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76900836100 + 56409575049 = 277310^2 + 237507^2 .

It is a cyclic number.

It is not a de Polignac number, because 133310411149 - 223 = 133302022541 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133310411149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133310411119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66655205574 + 66655205575.

It is an arithmetic number, because the mean of its divisors is an integer number (66655205575).

Almost surely, 2133310411149 is an apocalyptic number.

It is an amenable number.

133310411149 is a deficient number, since it is larger than the sum of its proper divisors (1).

133310411149 is an equidigital number, since it uses as much as digits as its factorization.

133310411149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 133310411149 in words is "one hundred thirty-three billion, three hundred ten million, four hundred eleven thousand, one hundred forty-nine".