Base | Representation |
---|---|
bin | 1100000111111110000000… |
… | …1010011001010101111011 |
3 | 1202012102202101211111002021 |
4 | 3001333200022121111323 |
5 | 3221403434322403430 |
6 | 44204110333415311 |
7 | 2544064464152134 |
oct | 301774012312573 |
9 | 52172671744067 |
10 | 13331044341115 |
11 | 427a733a99a56 |
12 | 15b378b93a537 |
13 | 75915c342a27 |
14 | 341324182c8b |
15 | 181b874ae07a |
hex | c1fe029957b |
13331044341115 has 16 divisors (see below), whose sum is σ = 16102873785888. Its totient is φ = 10594482552576.
The previous prime is 13331044341037. The next prime is 13331044341143. The reversal of 13331044341115 is 51114344013331.
It is a cyclic number.
It is not a de Polignac number, because 13331044341115 - 213 = 13331044332923 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2043984 + ... + 5553373.
It is an arithmetic number, because the mean of its divisors is an integer number (1006429611618).
Almost surely, 213331044341115 is an apocalyptic number.
13331044341115 is a deficient number, since it is larger than the sum of its proper divisors (2771829444773).
13331044341115 is a wasteful number, since it uses less digits than its factorization.
13331044341115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7599678.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 13331044341115 its reverse (51114344013331), we get a palindrome (64445388354446).
The spelling of 13331044341115 in words is "thirteen trillion, three hundred thirty-one billion, forty-four million, three hundred forty-one thousand, one hundred fifteen".
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