Base | Representation |
---|---|
bin | 111110000100111110… |
… | …1001110111011010111 |
3 | 110202002200020011002102 |
4 | 1330021331032323113 |
5 | 4141010111024142 |
6 | 141124154032315 |
7 | 12426400040633 |
oct | 1741175167327 |
9 | 422080204072 |
10 | 133311033047 |
11 | 5159a66a285 |
12 | 21a0571869b |
13 | c756b4a99a |
14 | 6649117dc3 |
15 | 3703895532 |
hex | 1f09f4eed7 |
133311033047 has 2 divisors, whose sum is σ = 133311033048. Its totient is φ = 133311033046.
The previous prime is 133311032999. The next prime is 133311033077. The reversal of 133311033047 is 740330113331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133311033047 - 226 = 133243924183 is a prime.
It is a super-2 number, since 2×1333110330472 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133311033077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66655516523 + 66655516524.
It is an arithmetic number, because the mean of its divisors is an integer number (66655516524).
Almost surely, 2133311033047 is an apocalyptic number.
133311033047 is a deficient number, since it is larger than the sum of its proper divisors (1).
133311033047 is an equidigital number, since it uses as much as digits as its factorization.
133311033047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 29.
Adding to 133311033047 its reverse (740330113331), we get a palindrome (873641146378).
The spelling of 133311033047 in words is "one hundred thirty-three billion, three hundred eleven million, thirty-three thousand, forty-seven".
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