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133312033020130 = 2513331203302013
BaseRepresentation
bin11110010011111100100000…
…010111110101100011100010
3122111000111122210110100102021
4132103330200113311203202
5114433141020423121010
61151310411424012054
740036322311652446
oct3623744027654342
9574014583410367
10133312033020130
1139528352225338
1212b5092216102a
135950369b6a033
1424cc4a036c826
151062b42a908da
hex793f205f58e2

133312033020130 has 8 divisors (see below), whose sum is σ = 239961659436252. Its totient is φ = 53324813208048.

The previous prime is 133312033020091. The next prime is 133312033020211. The reversal of 133312033020130 is 31020330213331.

It can be written as a sum of positive squares in 2 ways, for example, as 126445594508809 + 6866438511321 = 11244803^2 + 2620389^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 133312033020095 and 133312033020104.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6665601650997 + ... + 6665601651016.

Almost surely, 2133312033020130 is an apocalyptic number.

133312033020130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133312033020130 is a deficient number, since it is larger than the sum of its proper divisors (106649626416122).

133312033020130 is a wasteful number, since it uses less digits than its factorization.

133312033020130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13331203302020.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 133312033020130 its reverse (31020330213331), we get a palindrome (164332363233461).

The spelling of 133312033020130 in words is "one hundred thirty-three trillion, three hundred twelve billion, thirty-three million, twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 13331203302013 26662406604026 66656016510065 133312033020130