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133312111422277 is a prime number
BaseRepresentation
bin11110010011111100100101…
…000010111010101101000101
3122111000111212020222120221111
4132103330211002322231011
5114433141201011003102
61151310423304245021
740036324253242234
oct3623744502725505
9574014766876844
10133312111422277
1139528392504aa7
1212b50944470771
13595038018b038
1424cc4aa93ab1b
151062b498cacd7
hex793f250bab45

133312111422277 has 2 divisors, whose sum is σ = 133312111422278. Its totient is φ = 133312111422276.

The previous prime is 133312111422211. The next prime is 133312111422311. The reversal of 133312111422277 is 772224111213331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104832022040001 + 28480089382276 = 10238751^2 + 5336674^2 .

It is a cyclic number.

It is not a de Polignac number, because 133312111422277 - 219 = 133312110897989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133312111420277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656055711138 + 66656055711139.

It is an arithmetic number, because the mean of its divisors is an integer number (66656055711139).

Almost surely, 2133312111422277 is an apocalyptic number.

It is an amenable number.

133312111422277 is a deficient number, since it is larger than the sum of its proper divisors (1).

133312111422277 is an equidigital number, since it uses as much as digits as its factorization.

133312111422277 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 84672, while the sum is 40.

The spelling of 133312111422277 in words is "one hundred thirty-three trillion, three hundred twelve billion, one hundred eleven million, four hundred twenty-two thousand, two hundred seventy-seven".