Base | Representation |
---|---|
bin | 1100000111111110101000… |
… | …0111010011010110110011 |
3 | 1202012110012000222222210201 |
4 | 3001333222013103112303 |
5 | 3221404310043133243 |
6 | 44204135100140031 |
7 | 2544101562253405 |
oct | 301775207232663 |
9 | 52173160888721 |
10 | 13331211302323 |
11 | 427a80a266422 |
12 | 15b3817837617 |
13 | 759187accb45 |
14 | 34133c404b75 |
15 | 181b96e8e04d |
hex | c1fea1d35b3 |
13331211302323 has 4 divisors (see below), whose sum is σ = 13453515993280. Its totient is φ = 13208906611368.
The previous prime is 13331211302309. The next prime is 13331211302371. The reversal of 13331211302323 is 32320311213331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13331211302323 - 217 = 13331211171251 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13331211302291 and 13331211302300.
It is not an unprimeable number, because it can be changed into a prime (13331211309323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61152345315 + ... + 61152345532.
It is an arithmetic number, because the mean of its divisors is an integer number (3363378998320).
Almost surely, 213331211302323 is an apocalyptic number.
13331211302323 is a deficient number, since it is larger than the sum of its proper divisors (122304690957).
13331211302323 is a wasteful number, since it uses less digits than its factorization.
13331211302323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122304690956.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 13331211302323 its reverse (32320311213331), we get a palindrome (45651522515654).
The spelling of 13331211302323 in words is "thirteen trillion, three hundred thirty-one billion, two hundred eleven million, three hundred two thousand, three hundred twenty-three".
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