13331230213111 has 2 divisors, whose sum is σ = 13331230213112. Its totient is φ = 13331230213110.

The previous prime is 13331230213087. The next prime is 13331230213117. The reversal of 13331230213111 is 11131203213331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13331230213111 - 2¹⁹ = 13331229688823 is a prime.

It is a super-4 number, since 4×13331230213111⁴ (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13331230213117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665615106555 + 6665615106556.

It is an arithmetic number, because the mean of its divisors is an integer number (6665615106556).

Almost surely, 2^{13331230213111} is an apocalyptic number.

13331230213111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331230213111 is an equidigital number, since it uses as much as digits as its factorization.

13331230213111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13331230213111 its reverse (11131203213331), we get a palindrome (24462433426442).

The spelling of 13331230213111 in words is "thirteen trillion, three hundred thirty-one billion, two hundred thirty million, two hundred thirteen thousand, one hundred eleven".