Base | Representation |
---|---|
bin | 1100000111111110101101… |
… | …0010110111101101101111 |
3 | 1202012110020102021102122012 |
4 | 3001333223102313231233 |
5 | 3221404330131041142 |
6 | 44204141044511435 |
7 | 2544102222530612 |
oct | 301775322675557 |
9 | 52173212242565 |
10 | 13331231112047 |
11 | 427a81a4667a2 |
12 | 15b38223ab57b |
13 | 75918bc47784 |
14 | 341340cc0179 |
15 | 181b98aa3882 |
hex | c1feb4b7b6f |
13331231112047 has 2 divisors, whose sum is σ = 13331231112048. Its totient is φ = 13331231112046.
The previous prime is 13331231112011. The next prime is 13331231112107. The reversal of 13331231112047 is 74021113213331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13331231112047 - 212 = 13331231107951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13331231112007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665615556023 + 6665615556024.
It is an arithmetic number, because the mean of its divisors is an integer number (6665615556024).
Almost surely, 213331231112047 is an apocalyptic number.
13331231112047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331231112047 is an equidigital number, since it uses as much as digits as its factorization.
13331231112047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 13331231112047 its reverse (74021113213331), we get a palindrome (87352344325378).
The spelling of 13331231112047 in words is "thirteen trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred twelve thousand, forty-seven".
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